I have attached a picture.
In that we have to show that
1. Δ ACD is congruent to Δ BDC
2. BC = AD
3. angle A = angle B
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1. given
angle ACD =angle BDC
CD=CD (common)
to proof
triangle ACD is congruent to triangle BDC
proof
angle D = angle C
CD =CD
hence prooved by asa angle side angle property
2. yes by cpct
3. yes by cpct
angle ACD =angle BDC
CD=CD (common)
to proof
triangle ACD is congruent to triangle BDC
proof
angle D = angle C
CD =CD
hence prooved by asa angle side angle property
2. yes by cpct
3. yes by cpct
samkitjain51:
ur wrong that angle acd= angle bcd
no i am correct
how
angle acb = angle bda
thats only what i had written
its BDC
see diagram it show that angle acb=angle bda
and angle bcd = angle adc
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hope my answer will help u
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