Question

I have attached my question in picture pls solve it I will mark u brainliest​

Answer 1

1:1is the answer

because the

$t = 2\pi \div w \times \frac{?}{?}$

Answer 2

$\large\sf{\underbrace{\red{SOLUTION:-}}}$

GIVEN :-

• Both the particles complete on the circle in the same time ‘t’ .

CALCULATION :-

✴️ we have know that,

$\bigstar\:\rm{\purple{\boxed{Angular\:speed\:(\omega)\:=\:\dfrac{2\pi}{t}\:}}}$

▼ Now,

• $\rm{\omega_{1}\:=\:\dfrac{2\pi}{t}\:}$

• $\rm{\omega_{2}\:=\:\dfrac{2\pi}{t}\:}$

☞ Therefore, the ratio of Angular speed of the 1st to that of 2nd is,

$\rm{\implies\:\dfrac{\omega_{1}}{\omega_{2}}\:=\:\dfrac{\dfrac{2\pi}{t}}{\dfrac{2\pi}{t}}\:}$

$\rm{\boxed{\implies\:\dfrac{\omega_{1}}{\omega_{2}}\:=\:\dfrac{1}{1}}}$