Chemistry, asked by 2222harmankamboj, 6 hours ago

I have been told that applying POAC in any equation means conserving the number of moles of an element in both reactant and product . For example :
KClO3=KCl+O2

Here when we apply POAC on oxygen we write :

Equation 1 :

No. Of Atoms(or moles KClO3 ) of "O" in reactant = No. Of Atoms(or moles O2) of "O" in product

Equation 2: (obtained from equation 1)

3(moles of KClO3 ) = 2(moles of O2 )

Where equation 3 gives us the necessary data required in solving questions of stoichiometric calculations . I understand how equation 2 comes from equation 1 but I don't understand why equation 1 is correct even when the chemical equation is unbalanced ?

As I think equation 1 can be applied only when the chemical equation is balanced . As here :

No. Of Atoms of "O" in reactant =3

No of Atoms of "O" in product =2

Thus by equation 1 we can say that 3=2

And my book says POAC can be applied even when equation is not balanced . So here equation is not balanced and when I apply POAC I get 3=2 (but here How can the number of moles of chemical can be same even though equation is not same)​

Answers

Answered by sanjaakash2008
1

Answer:

No of Atoms of "O" in product =2

Thus by equation 1 we can say that 3=2

And my book says POAC can be applied even when equation is not balanced . So here equation is not balanced and when I apply POAC I get 3=2 (but here How can the number of moles of chemical can be same even though equation is not sam

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