I have been working in a while and it was not a big deal to me that I haveb
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4a
2
+b
2
+9c
2
−4ab−6bc+12ca
=(2a)
2
+(−b)
2
+(3c)
2
−2(2a)(b)−2(b)−2(b)(3c)+2(3c)(2a)
Using identity =(A+B+C)
2
=A
2
+B
2
+C
2
+2AB+2BC+2CA...........(i)
=(2a)
2
+(b)
2
+(3c)
2
+2(2a)(−b)+2(3c)(−b)+2(2a)(3c)
=(2a−b+3c)
2
( using Identity )
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Step-by-step explanation:
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