Question

I have been working in a while and it was not a big deal to me that I haveb​

Answer 1

Answer:

ANSWER

4a

2

+b

2

+9c

2

−4ab−6bc+12ca

=(2a)

2

+(−b)

2

+(3c)

2

−2(2a)(b)−2(b)−2(b)(3c)+2(3c)(2a)

Using identity =(A+B+C)

2

=A

2

+B

2

+C

2

+2AB+2BC+2CA...........(i)

=(2a)

2

+(b)

2

+(3c)

2

+2(2a)(−b)+2(3c)(−b)+2(2a)(3c)

=(2a−b+3c)

2

( using Identity )

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Answer 2

Step-by-step explanation:

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