Question

I have drawn a right angle triangle ABC whose Hypotemienuse AB 10 cm Bass BC8cm and Perpendicular AC 6 cm.Let us determine the value of sine and tangent angle ABC​

Answer 1

Let ABC is a right angled triangle at B

Base=BC=6cm

HypotenuseAC=10cm

Using Pythagoras theorem,

AC²=AB²+BC²

AB²=AC² −BC²

=10 ²−6²

=100−36

AB= √64

=8cm

Altitude=AB=8 cm

Now , Area of triangle = 1/2×base×altitude

= 1/2×6×8

=24cm ²

Answer 2

Answer:

Let ABC is a right angled triangle at BBase=BC=6cmHypotenuseAC=10cm Using Pythagoras theorem,AC²=AB²+BC² AB²=AC² −BC² =10 ²−6² =100−36

AB= ✓64

= 64 ᴄᴍ

Step-by-step explanation:

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