Question

I have drawn an isosceles triangle ABC whose included angle of two equal sides is angle ABC = 45° ; the bisector of angle ABC intersects the side AC at point D . Determine the circular values of angle(ABD,BAD,CBD,BCD)​

Answer 1

Answer:

∠ABC = 45°

∵ BD is the angle bisector of ∠ABC

∠BAD + ∠ABC+ ∠BCD = π

∵ ABC is an isosceles triangle

⇒ ∠BAD = ∠BCD = x

Answer 2

Step-by-step explanation:

Register

1

2

3

4

5

6

7

8

9

10

11

12

13

14 A1

14 A2

14 A3

14 A4

14 A5

14 B

14 C

15 A1

15 B

15 C

15 D

15 E

Q. 11

4.1

( 15 Votes )

I have drawn an i

Class 10th

West Bengal Board - Mathematics

20. Trigonometry: Concept of Measurement of Angle

Answer

∠ABC = 45°

∵ BD is the angle bisector of ∠ABC

∠BAD + ∠ABC+ ∠BCD = π

∵ ABC is an isosceles triangle

⇒ ∠BAD = ∠BCD = x