I have drawn an isosceles triangle ABC whose included angle of two equal sides is angle ABC = 45° ; the bisector of angle ABC intersects the side AC at point D . Determine the circular values of angle(ABD,BAD,CBD,BCD)
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Answer:
∠ABC = 45°
∵ BD is the angle bisector of ∠ABC
∠BAD + ∠ABC+ ∠BCD = π
∵ ABC is an isosceles triangle
⇒ ∠BAD = ∠BCD = x
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Q. 11
4.1
( 15 Votes )
I have drawn an i
Class 10th
West Bengal Board - Mathematics
20. Trigonometry: Concept of Measurement of Angle
Answer
∠ABC = 45°
∵ BD is the angle bisector of ∠ABC
∠BAD + ∠ABC+ ∠BCD = π
∵ ABC is an isosceles triangle
⇒ ∠BAD = ∠BCD = x
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