Question

i have got 5 but after i can't
please answer fast

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

(1+cotA-cosecA)(1+tanA+secA)

=[1+cosA/sinA-1/sinA][1+sinA/cosA+1/cosA]

=[sinA + cosA - 1÷sinA][cosA + sinA + 1÷cosA]

=(sinA+cosA)² - 1²÷sinAcosA

=sin²A+cos²A+2sinAcosA-1÷sinAcosA

=1+2sinAcosA-1÷sinAcosA

=2sinAcosA/sinAcosA

=2