i have got 5 but after i can't
please answer fast
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Step-by-step explanation:
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Answered by
1
Answer:
Step-by-step explanation:
(1+cotA-cosecA)(1+tanA+secA)
=[1+cosA/sinA-1/sinA][1+sinA/cosA+1/cosA]
=[sinA + cosA - 1÷sinA][cosA + sinA + 1÷cosA]
=(sinA+cosA)² - 1²÷sinAcosA
=sin²A+cos²A+2sinAcosA-1÷sinAcosA
=1+2sinAcosA-1÷sinAcosA
=2sinAcosA/sinAcosA
=2
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