Math, asked by naman112iscool, 1 year ago

I have got some chocolates to be distributed. When they are put in packets of 2, 3, 4, or 5 each, I am left with one. If they are put in packets of seven, I am left with none. What is the minimum number of chocolates that I have? Please answer

Answers

Answered by mhanifa
3

Answer:

301

Step-by-step explanation:

LCM(2,3,4,5)=60

We need to find a minimum number in the format of 60a+1=7k

Lets try with value of a starting from 1

61- not divisible by 7

121- not divisible by 7

181- not divisible by 7

241- not divisible by 7

301/7=43, so 301 is the minimum required number

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