Question

I have learnt that sin i/sin r is equal to a constant (Snell’s law).AND that constant is equal to the refractive index of second medium with respect to the first .
Also n1sin i= n2sin r .
So using this formula how do you obtain the refractive index of second medium????
I am confused as I got n2/n1 = sin i/sin r .
But shouldn’t this be the refractive index of medium 1 . PLEASE HELP ME !!

Answer 1

Answer:

When a ray of light passes from medium-1 to medium-2, then the ratio of sine of angle of incidence(i) to sine of angle of refraction(r) is equal to the refractive index of medium-2 (n

2

) relative to medium-1 (n

1

).

sinr

sini

=

n

1

n

2

⟹n

1

sini=n

2

sinr

Answer 2

Answer:

sorry yaar

samaj me nahi aa raha