Question

I have one doubt. sinx/n=6. how?????​
plzz answer my question correctly
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Answer 1

Answer:

hence proved

ha ha ha nice question

Answer 2

Answer:

- ni (ln √71 ) ± nπ/4

Step-by-step explanation:

sinx/n = 6

it is known that the sine function is governed by this inequality

-1 ≤  sinx ≤ 1  

in the domain of real numbers

but we can find a solution in the domain of complex numbers

so far ;

let x/n = y , sin x/n = sin y = 6

sin y = 6 = (e^iy - e^-iy)/2i  ,  i is the immaginery unit = √-1

e^iy - e^-iy = 12i , let e^iy = k

k - 1/k = 12i

k² - 12ik -1 = 0

k = (12i ± √-140)/2 = 6i ±√35 i ≈ √71 e∧±iπ/4 = e∧iy

iy = (ln √71 ) ± iπ/4 = ix/n

ix = n (ln √71 ) ± inπ/4

x = - ni (ln √71 ) ± nπ/4