Question

I have paid Rs.100 to iron saree, pant and shirt. Cost of ironing a saree is two times that of a shirt. Pant's cost is Rs.20 less than that of a saree. Find the cost of Saree?

Answer 1

Cost of ironing a saree is two times that of shirt .

Let the cost of ironing a shirt be x .

Then the cost of ironing a saree will be 2 x .

Cost of ironing the pant is Rs 20 less than that of saree .

So the cost will be 2 x - 20 .

Now the total cost of ironing is Rs 100 .

2 x - 20 + x + 2 x = 100

⇒ 5 x - 20 = 100

⇒ 5 x = 120

⇒ x = 120/5

⇒ x = 24

Thus the value of x is Rs 24 .

The cost of ironing the saree will be 2 x .

The cost will be Rs 24 × 2 = Rs 48 .

Thus the cost of ironing the saree will be Rs 48 .

Answer 2

$\huge{\mathfrak{</p><p><strong>Answer:</strong></p><p>}}$

$\huge{\sf{<strong>A</strong><strong>.</strong><strong>T</strong><strong>.</strong><strong>Q</strong>}}$

$\large{\sf{Let\:the\:cost\:of \:Saree \: be\:2x }}$

$\large{\sf{Let \:the \:cost \:of \:shirt\: be\: x}}$

$\large{\sf{Let \:the \:cost\: of\: pant\: be\: 2x - 20}}$

$\large{\sf{x + 2x + 2x - 20 = 100}}$

$\large{\sf{5x - 20= 100}}$

$\large{\sf{5x = 100 + 20}}$

$\large{\sf{5x = 120}}$

$\large{\sf{x = 120/5}}$

$\large{\sf{x = 24 Rupees}}$

$\huge{\bf{Cost\:of\:ironing\:shirt\:= 24 Rupees}}$

$\huge{\bf{Cost\:of\:ironing \:Saree = 2x = 2(24) = 48 Rupees}}$

$\huge{\bf{Cost\:of\:ironing \:pant\:= 2x - 20 = 2(24) - 20 = 48 - 20 = 28 Rupees}}$