Question

I have prepared a beverage with syrup and water is the ratio of 5:2. What part ofdrink will be removed and replaced so that the volume of the syrup and water becoms equal? ​

Answer 1

Let the vessel contains 8 litres of liquid.

Let x litres of this liquid be replaced with water

when x litre of mixture is taken out it means

8

5x

litre milk and

8

3x

litre water taken out

Quantity of water in new mixture =(3−

8

3x

+x)litres

Quantity of milk in new mixture =(5−

8

5x

)litres

∴(3−

8

3x

+x)=(5−

8

5x

)

⇒5x+24=40−5x

⇒10x=16

∴x=

5

8

So, part of the mixture replaced =(

5

8

×

8

1

)=

5

1

.