Question

I have problems in Math so can someone help me?

1. Arrange 5/4, 3/5 and 11/8 in order, beginning with the smallest.

2. Which is greater, 9/2 or 3 4/5?

3.Arrange 2/5, 1 7/9 and 3/2 in increasing order.

Thanks if you help :)

Answer 1

$\huge\sf\green {☺Hello\:Mate☺}$

To find there answers we need same denominators.

$\huge\sf\purple {Here\:we\:go⤵}$

1. Arrange 5/4, 3/5 and 11/8 in order, beginning with the smallest.

$\frac{5}{4} = \frac{5 \times 10}{4 \times 40} = \frac{50}{40}$

$\frac{3}{5} = \frac{3 \times 8}{5 \times 8} = \frac{24}{40}$

$\frac{11}{8} = \frac{11 \times 5}{8 \times 5} = \frac{55}{40}$

So the ascending order will be $\frac{24}{40} = \frac{3}{5} ,\frac{50}{40} = \frac{5}{4}, \frac{55}{40} = \frac{11}{8}$

= $\frac{3}{5} ,\frac{5}{4} ,\frac{11}{8}$

2. Which is greater, 9/2 or 3 4/5?

$\frac{9}{2} = \frac{9 \times 5}{2 \times 5} = \frac{45}{10}$

$3 \frac{4}{5} = \frac{19}{5} = \frac{19 \times 2}{5 \times 2} = \frac{38}{10}$

$\frac{45}{10} = \frac{9}{2} > \frac{38}{10} = 3 \frac{4}{5}$

$= \frac{9}{2} > 3 \frac{4}{5}$

3. Arrange 2/5, 1 7/9 and 3/2 in increasing order?

$\frac{2}{5} = \frac{2 \times 18}{5 \times 18} = \frac{36}{90}$

$\frac{17}{9} = \frac{17 \times 10}{9 \times 10} = \frac{170}{90}$

$\frac{3}{2} = \frac{3 \times 45}{2 \times 45} = \frac{135}{90}$

$= \frac{36}{90},\frac{135}{90} , \frac{170}{90}$

= $\frac {2}{5}, \frac {3}{2}, \frac {17}{9}$

Please mark me as brainliest...

$\huge\mathfrak\red {hope\:it\:helpss}$