Math, asked by adnanrashid064, 11 months ago

I have the answers ​

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Answered by AlluringNightingale
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2. Solution :

=> 2x² - 7x + 3 = 0

=> 2x² - 6x - x + 3 = 0

=> 2x(x - 3) - (x - 3) = 0

=> (x - 3)(2x - 1) = 0

=> x = 3 , 1/2

4. Solution :

=> 2x² + x - 4 = 0

=> 2(x² + x/2 - 2) = 0

=> x² + x/2 - 2 = 0

=> x² + x/2 + (1/4)² - (1/4)² - 2 = 0

=> x² + 2•x•(1/4) + (1/4)² = (1/4)² + 2

=> (x + 1/4)² = 1/16 + 2

=> (x + 1/4)² = (1 + 32)/2

=> (x + 1/4)² = 33/2

=> x + 1/4 = ± √(33/2)

=> x = -1/4 ± √(33/2)

=> x = -1/4 + √(33/2) , -1/4 - √(33/2)

7. Solution :

=> √2x² - 3x - 2√2 = 0

=> √2x² - 4x + x - 2√2 = 0

=> √2x(x - 2√2) + (x - 2√2) = 0

=> (x - 2√2)(√2x + 1) = 0

=> x = 2√2 , -1/√2

9. Solution :

=> x² - (√2 + 1)x + √2 = 0

=> x² - √2x - x + √2 = 0

=> x(x - √2) - (x - √2) = 0

=> (x - √2)(x - 1) = 0

=> x = √2 , 1

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