Question

I have three questions:

1, if the width of a garden is 1/5 of its length and the perimeter is 60m , find the length of the garden.

2,if the sum of three consecutive multiples of 15 is 270, then find the smallest number.

7 1/2 meters long rope is cut into 8 equal pieces. What is the length of each piece ?

Advanced thankyou for answering

Answer 1

Answer:

1 width is 1/5 th of its length so

let the length be x and width be 1x/5

so perimeter of rectangle is 2 ( length + width)

2(x/5+x)=60

60/2 = (5x +x /5)

30 =6x/5

30×5=6x

150=6x

x=150/6

x=25

2 let the consecutive no be x ,x+15,x+30

so x+x+15+x+30=270

3x+45=270

3x=270-45

3x=225

x=225/3

x =75

3 71/2 i.e. 35.5 /8 = 4.45 m

Answer 2

1)let the length of garden be x and breadth be 1/5x.

perimeter of garden = 2×(l+b)

60 = 2×(x + 1/5x)

60 = 2×(5x/5 + 1/5x)

60 = 2 × 6x/5

60/2 = 6x/5

30×5 = 6x

6x = 150

x = 150/6

x = 25m

therefore, length of garden = 25m

2)let the required 3 number be x , x+15 and x+30

x + (x+15) + (x+30) = 270

3x + 45 = 270

3x = 225

x =225/3

x = 75

The 3 numbers are :- 75 , 90 and 105

Hence,smallest number is 75.

3)Length of each piece = 1/2 ÷ 8

= 1/2 × 1/8

= 1/16 meter Hence , length of each piece = 1/16meter

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