i have total of rupee 300 coins of demonstration rupee 1, rupee 2, rupee 5.the number of rupee 2 is three times the number of rupee 5 . total number of coin is 160. how many coins of each demonstration are with me .
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Answer:
rs 1 - 80 coins
rs 2 - 60 coins
rs 3 - 20 coins
Step-by-step explanation:
let the no. of rs 5 coins = x
& the no. of rs 1 coin = y
& no. of rs 2 coins = 3 x
a.q.t total no. of coins = 160
x + 3x+y = 160
4x + y = 160 (eq. 1)
total rs = 300
5x + 2(3x) + 1y = 300
11x + y = 300 (eq. 2)
by elimination method
on subtracting both the equations
4x + y = 160
-11x -y = -300
=-7x =-140
x =20
on putting the the value of x in eq 2
4(20) + y =160
80 + y = 160
y =80
now,
no of rs 2 coins = 3(20) = 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
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