I have total rupees 300 in in coins denomination rupees 1 rupees rupees 2 and rupees 5.
the number of rupees to coins is three times the number of rupees 5 coins. the total number of coins is 160. how many coins of each denomination are with me?
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Answer:
let the no. of rs 5 coins be x
& the no. of rs 1 coin be y
& no. of rs 2 coins be 3 x
a.q.t total no. of coins = 160
x + 3x+y = 160
4x + y = 160 eq. 1
again a.q.t total rs = 300
5x + 2(3x) + 1y = 300
11x + y = 300 eq. 2
by elimination method
on subtracting both the equations
4x + y = 160
-11x -y = -300
=-7x =-140
x =20
on putting the the value of x in eq 2
4(20) + y =160
80 + y = 160
y =80
now,
no of rs 2 coins = 3(20) = 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
Please mark me as Brainless
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