I have tried but I am not getting the solution of the question solve it.
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s = t²/3
v = ds/dt
= d (t²/3) / dt
= 2t/3
a = dv/dt
= d (2t/3) / dt
= 2/3 m/s²
F = ma
= 3kg × (2/3) m/s²
= 2 N
Work = F × S
= F × (0.5at²) ………[∵ Body was initially at rest, u = 0]
= 2 N × (0.5 × (2/3 m/s²) × (2 s)²)
= 8/3 J
Work done by force is 8/3 Joules
(c) is the correct option.
v = ds/dt
= d (t²/3) / dt
= 2t/3
a = dv/dt
= d (2t/3) / dt
= 2/3 m/s²
F = ma
= 3kg × (2/3) m/s²
= 2 N
Work = F × S
= F × (0.5at²) ………[∵ Body was initially at rest, u = 0]
= 2 N × (0.5 × (2/3 m/s²) × (2 s)²)
= 8/3 J
Work done by force is 8/3 Joules
(c) is the correct option.
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