Question

I have understood the reactions

taking place in beakers ‘A’ and

‘B’. But I am still confused why

there is no change in beakers

‘C’, ‘D’ and ‘E’?​

Answer 1

Answer:

as it is only visible for beaker C

Explanation:

i can say it have no change because of reactivity series or spectrochemical series by which Cu can't displace Zn from its salt solution as Zn is higher reactive than Cu

for rest 2 beakers I guess same scenario will work!