Question

I heat engine performs 1000J OF WORK AND AT THE SAME TIME rejectS 4000J of heat energy to the cold reservoir.what is the efficiency of the engine if the difference of the temperature between the sink and the source of this engine is 75C. FIND THE TEMPERATURE OF THE SOURCE? Also show Your work!!​

Answer 1

FORMULAE: 1-n%=dW/dQ, 2-n%=dt/t2, 3-dt=t2-t1, 4-dQ=dW+du

n%=dW/dQ

n%=1000/4000

n%=0.25

n%=dt/t2

0.25=75/t2

t2=75/0.25

t2=300k (temp. of sink)

dt=t2-t1

75=300-t1

t1=225k(temp. of the source)

dQ=dW+du

-4000=1000+dU

dU=-4000-1000

dU=-5000J

Answer 2

Answer:

hope it will help you.......