Question

I hope someone will answer ​

Answer 1

Explanation:

Oxygen is a diatomic gas

It's molar massis16×2=32g

So,32g of oxygen occupies 22.4 dm³ at S.T.P

16g of oxygen will occupy 22.4/32×16=11.2dm³

Thus,

P¹=1atm P²=?

V¹=11.2 dm³. V²=1dm³

T¹=273 k. T²=273+25=298 k

By gas equation

P¹V¹/T¹=P²V²/T²

P²=1×11.2 ×298/273×1=12.2atm

Answer 2

A N S W E R:

As you know,

Oxygen is a diatomic gas

It's molar massis = 16 × 2 = 32g

So,

32g of oxygen occupies

22.4 dm³ at S.T.P

And

16g of oxygen will occupy

22.4/32 × 16 = 11.2dm³

Thus,

P¹ = 1atm

P² = ?

V¹ = 11.2 dm³

V² = 1dm³

T¹ = 273 k

T² = 273+25 = 298 k

By gas equation

P¹V¹/T¹=P²V²/T²

P² =1 ×11.2 × 298/273 × 1

Ans =12.2atm