Question

(i) How many Ag atoms are there in 0·0001 gram of Ag. Molar mass of Ag is 108 gram per mole. (ii) Calculate the number of moles of CO2 having 6·022 x 1022 molecules in it.

Answer 1

(1) m/M=N/$N_{0}$

0.0001/108=N/$6.022*10^{22}$

N=5.575*$10^{22}$atoms

(2)n=N/$N_{0}$

n=$6.022*10^{22}$/$6.022*10^{22}$

n=1 mol