Question

I hv attached the question plss check nd solve it​

Answer 1

Step-by-step explanation:

$\sf ({\frac{ 1 + cos\theta }{sin\theta}})^{2}$

$\sf = \frac {{ 1 + cos\theta }^{2}}{{sin}^{2}\theta}$

$\sf = \frac {{1 + cos\theta}^{2}}{1-{cos}^{2}\theta}$

$\sf = \frac {{1 + cos\theta}^{2}}{( 1+cos\theta)(1-cos\theta)}$

$\sf = \frac { 1 + cos\theta}{1-cos\theta}$

$\sf = R.H.S$

$\sf Hence\:proved$

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