Physics, asked by sdeepbera, 2 months ago

i=i0e^(-t/RC) find di/dt​

Answers

Answered by kanishkagupta1234
0

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Answered by Anonymous
1

Explanation:

i = i0e-t/RC I0 = 2A, R = 6 x 10-5 Ω, C = 0.0500 x 10-6 F = 5 x 10-7 F (a) i = 2 x e ((-0.3)/(6 x 0^3 x 5 x 〖10〗^(-7) )) = 2 x e((-0.3)/0.3) = 2/e amp. (b) di/dt = (-i_0)/RC e-t/RC when t = 0.3 sec ⇒ di/dt = - 2/0.30 e(-0.3/0.3) = (-20)/3e Amp/Sec (c) At t = 0.31 sec, I = 2e(-0.3/0.3) = 5.8/3e Amp

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