Question

i+i²+i³+i⁴........+i²⁰²⁰​

Answer 1

Imaginary Numbers

i = imaginary unit

i² = -1 or i = √-1

i⁰ = 1

i¹ = i

i² = -1

i³ = -i

i⁴ = 1

i⁵ = i

i⁶ = -1

i⁷ = -i

to raise i to an arbitrary higher power:

= i¹⁰⁰

= (i⁴)²⁵

= 1²⁵

= 1

= i⁵⁰¹

= i⁵⁰⁰ * i¹

= (i⁴)¹²⁵ ⋅ i¹

= i

√-9 = i√9 = 3i

(3i)² = 3² ⋅i² = 9 ⋅ -1 = -9

3i = √-9

Answer 2

Answer:

             the answer is 1

explanation: brother you first you divide 2020.then you get 505 and simplify it you get the answer