Math, asked by sharal23, 1 year ago

-i) If a and ß are zeroes of x2 + 8x + 6 find 1/a + 1/ß=

Answers

Answered by mukesh777
1

1/a +1/b = (a+ b)/ab

=(-8/1)/(6/1)

= -8/6

= -4/3

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