Question

(i) If a + b =12 and ab = 4, find the value of a3 + b3. pls fast

Answer 1

a3−b3=(a−b)(a2+ab+b2)

a3−b3=(a−b)(a2−2ab+b2+2ab+ab)

a3−b3=(a−b)[(a−b)2+3ab]

a3−b3=4×(42+3×45)=4×(16+135)=4×151=604

Answer 2

Answer:

a3+b3=(a+b)3_3ab(a+b)

=(12)3_3×4×12

=1728_144

=1584

The value of the a3+b3 is 1584

Step-by-step explanation:

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