(i) If a + b + c = 9 and ab + bc + ca = 40, find a^2+ b^2 + c^2
Answers
Answered by
0
Step-by-step explanation:
a+b+c=9
ab+bc+ca=40
We know that
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
9²=a²+b²+c²+2×40
81=a²+b²+c²+80
a²+b²+c²=81-80
a²+b²+c²=1
Hope it helps u....
Answered by
0
Answer:
(a+b+c)² = a² +b²+c²+ 2(ab+bc+ca)
9² = a²+b²+c²+2(40)
81= a²+b²+c²+80
81-80=a²+b²+c²
1 = a²+b² +c²
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