i. If a number has 'n' digits, then the number of digits in the square of the numbers
Answers
Given :a number has 'n' digits,
To Find : number of digits in the square of the numbers
Solution:
Number with 1 Digit
1 ≤ x < 10²
1 ≤ x² < 10²
1 ≤ x² < 100
Hence x² is 1 or 2 digit
a number x has '1' digits then square has 1 or 2 digit
Number with 2 Digit
10 ≤ x < 100
10² ≤ x² < 100²
10² ≤ x² < 10000
Hence x² is 2 or 2 digit
a number has '2' digits then square has 2 or 3 digit
Number with n Digit
1000..(n-1) times 0 ≤ x < 1000 (n times zero)
1000.. 2(n-1) times 0 ≤ x² < 1 000...... (2n times zero)
1 + 2(n- 1) = 2n-1 digits
1 + 2n = 2n + 1 digit
2n-1 digits ≤ x² < 2n + 1
Hence number of possible digits in x² are 2n-1 or 2n
Hence a number has 'n' digits then square has 2n-1 or 2n digit
if a number has 'n' digits, then the number of digits in the square of the numbers are 2n-1 or 2n
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