(i) If a² + b² + c² = 12 and a+b+c = 23 ,Find : ab+bc+ca.
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Formula,
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
=a2+b2+c2+2(ab+bc+ca)
Given,
⇒92=a2+b2+c2+2(23)
⇒81−46=a2+b2+c2
∴a2+b2+c2=35
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