i) If (AB)/(QR) = (BC)/(PR) = (AC)/(PQ) triangle ABC sim triangle PQR then write the proper one to one correspondence to show
Answers
Step-by-step explanation:
Since The Corresponding sides are equal we have to check whether while naming the Corresponding sides of the ∆les are equal or not↓
In Option 1,3&4
→we see it doesnt Fulfill the requirements which are given in the Question.
=> Option (2) is correct as it Proves the Requirement of Naming,
→∆PQR≈∆CAB [°≈ this sign = Similar ∆les]
We get,
→ \frac{PQ}{CA}
CA
PQ
= \frac{QR}{AB}
AB
QR
= \frac{PR}{BC}
BC
PR
↑its just the opposite of Given
Answer:
OK by
Step-by-step explanation:
QR
AB
=\frac{BC}{PR}
PR
BC
=\frac{CA}{PQ}
PQ
CA
\boxed{Proof:-}
Proof:−
→Since The Corresponding sides are equal we have to check whether while naming the Corresponding sides of the ∆les are equal or not↓
In Option 1,3&4
→we see it doesnt Fulfill the requirements which are given in the Question.
=> Option (2) is correct as it Proves the Requirement of Naming,
→∆PQR≈∆CAB [°≈ this sign = Similar ∆les]
We get,
→\frac{PQ}{CA}
CA
PQ
=\frac{QR}{AB}
AB
QR
=\frac{PR}{BC}
BC
PR
↑its just the opposite of Given