Question

(i) If f(x) =
$\sqrt{4 - {x}^{2} }$
, x € (-2, 2), find f'(x).​

Answer 1

Answer:

$f(x) = \sqrt{4 - {x}^{2} } \\ differentiate \: w \: r \: t \: x \\ f'(x) = \frac{1}{ 2\sqrt{4 - {x}^{2} } } \frac{d}{dx} (4 - {x}^{2} ) \\ = \frac{1}{2 \sqrt{4 - {x}^{2} } } (0 - 2x) \\ = - \frac{x}{ \sqrt{4 - {x}^{2} } }$

Answer 2

Answer:

this is correct.....................