Question

(i) If log (m + n) = log m + log n, show that m = n / n - 1


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Answer 1

Step-by-step explanation:

Given,

log(m+n) = logm + logn

log(m+n) = log(mn)

m + n = mn

n = mn - n

n = m(n-1)

m = n/( n - 1)

Answer 2

Answer:

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