Question

(i) If one of the angles of a parallelogram measures 75°, find the other angles​

Answer 1

Step-by-step explanation:

15 and 15 are the other 2 angles

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Answer 2

$\huge \mathcal \red {\underline{\underline{A}}} \huge \mathcal \green {\underline{\underline{N}}} \huge \mathcal \pink {\underline{\underline{S}}} \huge \mathcal \blue {\underline{\underline{W}}} \huge \mathcal \orange {\underline{\underline {E}}} \huge \mathcal \purple {\underline{\underline{R}}} ✧$

Let us consider a parallelogram ABCD with /_A = 75°.

$\large\bold\red{To \: find :-}$

/_B, /_C, /_D.

$\large\bold\red{properties \: used \: }$

◇ In parallelogram, sum of adjacent angles are 180°.

◇ In parallelogram, opposite angles are equal

Solution:-

We know,

/_A + /_B = 180° (Sum of adjacent angles)

75° + /_B = 180°

/_B = 180° - 75°

∴/_B = 105°

Now, in parallelogram opposite angles are equal.

∴/_A = /_C & /_B = /_D

∴/_C = 75° & /_D = 105°.

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