Question

(i)
If qcos O = P, find tan 0 - cot 0 in terms of p and q.
​

Answer 1

Answer:

qcos o=p

then

cos o=p/q

then we can find the value of sin o

therefore

sin o=under root a (q square - p square)/q

then

tan o - cot o

sin o/cos o - cos o/sin o

(sin^2 o - cos^2 o)/cos o sin o

then put the value of sin o and cos o from above which is given

then would be answer

(q^2 - 2p^2)/p under root a (q square - p square)

or

Answer 2

solition is in this pic