Question

(i) If the 5 term and the 11" term are 16 and 34 respectively, then find the
A.P.​

Answer 1

Step-by-step explanation:

a5 = a + 4d = 16 [ an = a + (n-1)d ]

or a = (16 - 4d) .. (1)

Similarly,

a11 = a + 10d = 34

or a = 34 - 10d

Using equation (1), we get

16 - 4d = 34 - 10d

10d - 4d = 34 - 16

6d = 18

d = 3

using d = 3 in equation (1)

a = 16 - 4(3)

a = 16-12 = 4

Therefore AP :

a1 = 4,

a2 = a + d = 7

a3 = a + 2d = 4 + 6 = 10 ...

Answer 2

Hope this helps..........