Question

(i) If the difference of the squares of two consecutive odd numbers is 40, find the larger number.

Answer 1

Answer:

larger number is 11

Step-by-step explanation:

$assume \: that \: smaller \: number \: is \: \: x \\ larger \: number \: is \: (x + 2) \\ defference \: of \: squares \: of \: two \: number \: is \: 40 \: \: so \: \\ ( {x + 2})^{2} - {x}^{2} = 40 \\ {x}^{2} + 4x + 4 - {x}^{2} = 40 \\ 4x + 4 = 40 \\ 4x = 40 - 4 = 36 \\ x = \frac{36}{4} \\ x = 9 \\ so \: smaler \: number \: is \: \: 9 \\ \: and \: larger \: number \: is \:( x + 2) = (9 + 2) = 11$

plzz mark as a brainliest answer