Question

(I) if the roots of the quadratic equation ( a square +b square)X square + 2(bc-ad)X + (c square+d square)= 0 are real and equal. show that ac+bd=0 (2) If the roots of the quadratic equation (c square - ab)x square - 2(a square - bc)X + b square - ac=0 are equal. prove that either a=0 (or) a cube + b cube + c cube = 3abc......... Pls answer ​

Answer 1

Answer:

we know that ,for real and equal roots

D=0 ~ B sqre - 4 A×C =0

so (bc- ad)sqre - 4 (a sqre +b sqre ) ×(c sqre +d sqre ) = 0

by solving we get

last answer is (ac+ bd)=0

Answer 2

Answer:

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