Question

(i) If the solubility of Pbl in water is x g mole per litre, then its solubility product is
given by
(a) x?
b.4xsqure
(c) 2x
(d) 4x​

Answer 1

Answer:

option b is the correct answer dear

Answer 2

If the solubility of Pbl in water is x g mole per litre, then its solubility product is( b)4xsqure

Explanation:

        PbI2⇌Pb2++2I−

                    x        2x

given solubility of PbI2 is 0.7Lg

also, molar mass of PbI2=461.2g/mol

⇒[PbI2]=461.20.7mol/Litre=1.5×10−3

solubility product, Ksp=x(2x)2

Ksp=4x3

Ksp=4(1.5×10−3)3

∴ Solubility product of PbI2=135×10−9mol2/lit2