Question

i if the square of hypotenuse of an isosceles right angle triangle is 242 sq.cm find the length of each of the other two side of the triangle​

Answer 1

Answer: The length of both the other two side of the triangle​ are 11 sq. cm  

Step-by-step explanation:

Given : c² = 242

            a=b (isosceles Δ)

To find : a and b

Formula : a² + b² = c² (Pythagoras theorem)

a² + a² = 242 (a=b)

2a² = 242

a² = 121

a = √121

a = 11 sq. cm

b = 11 sq. cm (a=b)

Please mark brainliest!

Answer 2

Answer:

Length of each of the other two side of the triangle are 11 cm.

Step-by-step explanation:

Given:

Square of the length of hypotenuse = 242 cm.

Let length of each equal side of isosceles right angle triangle = x cm.

As we know that,

$hypotenuse ^{2} =one side^{2} +other side^{2}$

  242 = $x^{2}$ +$x^{2}$

 242 = 2$x^{2}$

  $x^{2}$ = 242 /2

       = 121

   x=  $\sqrt{121}$ =11 cm.