Question

i) If y=√(sinx) find dy÷dx​

Answer 1

$y = \sqrt{sinx} \\ \\ \frac{dy}{dx} = \frac{d}{dx} \sqrt{sinx} \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{sinx} } \frac{d}{dx} sinx \\ \\ \frac{dy}{dx} = \frac{cosx}{2 \sqrt{sinx} }$