Math, asked by samruddhibongale, 6 days ago

i) In A ABC, ACB = 90° seg CD is perpendicular to seg AB seg DE is perpendicular to seg CB. Then show that CDsq. x AC = AD × AB × DE

Answers

Answered by mrignainishrivastava
1

Answer:

ऑनलाइन परामर्श केंद्र पर विचार विमर्श और यह सब कुछ एक बार फिर यह

Step-by-step explanation:

ऋण पर विचार विमर्श और यह सब कुछ एक

Answered by oOmisskillerOo
2

We have,

ABC is a right angle triangle.

In which ∠ACB=90

o

And CD⊥ABandDE⊥AB

Where D is any point in AB and E is any point in CB.

Prove that:- CD

2

×AC=AD×AB×DE

 \\  \\  \\

Attachments:
Similar questions