i) In A ABC, ACB = 90° seg CD is perpendicular to seg AB seg DE is perpendicular to seg CB. Then show that CDsq. x AC = AD × AB × DE
Answers
Answered by
1
Answer:
ऑनलाइन परामर्श केंद्र पर विचार विमर्श और यह सब कुछ एक बार फिर यह
Step-by-step explanation:
ऋण पर विचार विमर्श और यह सब कुछ एक
Answered by
2
We have,
ABC is a right angle triangle.
In which ∠ACB=90
o
And CD⊥ABandDE⊥AB
Where D is any point in AB and E is any point in CB.
Prove that:- CD
2
×AC=AD×AB×DE
Attachments:
Similar questions