Question

i. In a family of 3 children calculate the probability of having at least one boy

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Answer 1

Answer:

S = {1, 2, 3}

n(S) = 3

event A - at least one boy

A = {1, 2, 3}

n(A) = 3

p(A) = n(A)/n(S)

= 3/3

= 1

Answer 2

Step-by-step explanation:

Given

no. of children in a family =3

Total no. if outcomes =

${2}^{3}$

sample space = {BBB,BBG,BGB,BGG,GBB,GBG,GGB,GGG}

Probability= favourable number of outcome / total number of outcomes

Probabilitybility of having at least one boy = 7/8