(i) In an airthmetic progression d = -4, n = 7 and S,
4. then the value of a will be..
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Given : a = first term
d = common difference = -4
Sn = sum of all terms =4
n = total no of terms = 7
now using Sn formula,
Sn = n/2 x (2a + (n-1)d )
=> S7 = 7/2 x (2a + 6d)
4 = 7/2 x (2a + -24)
8 = 7 (2a-24)
8 = 14a - 168
14a = 176
a = 176/14
a = 88/7
hence the first term is 88/7.
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