(i) In the adjoining figure,the area of the cross roads is
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Answer:
636m².
Step-by-step explanation:
Area of the cross roads=(area of first road parallel to the length)+(area of second road parallel to the breadth)
=(l×b)+(l×b)
=[(200×2)+{(120-2)×2}]m²
=[400+(118×2)]m²
=[400+236]m²
=636m².
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