Question

(i) In the figure, ∆ ABC ~ ∆ MNO. D is the midpoint of side AC and P is the midpoint
of side MO, then
(a) Prove : ∆ABD ~ ∆MNP
(b) Prove. BD/NP = AB/MN

(C) Write your conclusion from the
result obtained in (b).​

Answer 1

Step-by-step explanation:

a part is done

hope it helps you!

Answer 2

∆ABD ≈ ∆MNP  & BD/NP = AB/MN

Step-by-step explanation:

∆ ABC ~ ∆ MNO

=> AB/MN = AC/MO = BC/NO

∠A = ∠M  

∠B = ∠N

∠C = ∠O

D is mid point of  AC

=> AD = DC = AC/2

P is mid point of MO

=> MP = OP = MO/2

=> AD/MP = (AC/2)/(MO/2) = AC/ MO

=> in ∆ABD & ∆MNP

AB/MN = AD/MP

& ∠A = ∠M

=> ∆ABD ≈ ∆MNP

AB/MN = AD/MP = BD/NP

=> BD/NP = AB/MN

=> ∆CBD ≈  ∆ONP

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in triangle ABC if,angle 1 = angle 2 prove that AB/AC=BD/DC ...

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