Question

I In the figure, two circular flower beds have been shown on the two sides of a square lawn ABCD of side 56 m. If the centre of each flower bed is the point of intersection O of the diagonals of the square lawn, find the sum of the areas of the lawn and the flower beds.

Answer 1

Answer:

HEY MATE, HERE IS UR ANSWER:-

Step-1

Side of square = 56cm

ΔAOB

AB²=OA²+OB²

56²=r² + r²

56×56=2r²

56×56÷2

⇒r²=56×28

Area of flower bed

⇒ Area of 2 sectors + area of 2 triangles

2×∅÷360 + 2×1/2×b×h

90÷180πr² + r² ( we get 90÷180 by cancellation)

1÷2 × 22÷7 ×56×28 + 56×28

88×28 + 56×28

⇒(88+56)×28

⇒144×28= 4032cm²

Therefore sum of the areas of the lawn and the flower bed = 4032cm²

I HOPE THIS HELPS U!!!

GOOD DAY,

BYE

Answer 2

Answer:

Side of square = 56cm

ΔAOB

AB²=OA²+OB²

56²=r² + r²

56×56=2r²

56×56÷2

⇒r²=56×28

Area of flower bed

⇒ Area of 2 sectors + area of 2 triangles

2×∅÷360 + 2×1/2×b×h

90÷180πr² + r² ( we get 90÷180 by cancellation)

1÷2 × 22÷7 ×56×28 + 56×28

88×28 + 56×28

⇒(88+56)×28

⇒144×28= 4032cm²

Step-by-step explanation: