Math, asked by manavrathore6250, 1 year ago

I integrate sin x e cosx dx-(sinx+cosx) e^(sinx+cosx)

Answers

Answered by krupakharchan
0

Step-by-step explanation:

∫e

x

(cosx−sinx)dx

=∫e

x

cosxdx−∫e

x

sinxdx

III

=cosxe

x

−∫−sinx⋅e

x

dx−∫e

x

sinxdx

=cosxe

x

+∫sinxe

x

dx−∫e

x

sinxdx

e

x

cosx+c

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