I^-+IO3^-+H^+=H2O+I2 BALANCE THIS EQUATION
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Explanation:
5 (I)- + IO3- + 6 H+ → 3 H2O + 3 I2
This is an oxidation-reduction (redox) reaction:
5 I-I - 5 e- → 5 I0
(oxidation)
IV + 5 e- → I0
(reduction)
I- is a reducing agent, IO3- is an oxidizing agent (synproportionation (comproportionation))
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